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5x^2-67x-120=0
a = 5; b = -67; c = -120;
Δ = b2-4ac
Δ = -672-4·5·(-120)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-83}{2*5}=\frac{-16}{10} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+83}{2*5}=\frac{150}{10} =15 $
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